Các câu hỏi tương tự
x+2/2006+x+3/2005+x+1/2004+x+5/2003=x+4/503
Tìm x: a, \(\frac{x-2004}{2003}+\frac{x-2003}{2004}+\frac{x-2005}{2004}=3+\frac{2005}{2003}\)\(+\frac{2004}{2005}\)
dfrac{x+5}{2005}+dfrac{x+6}{2004}+dfrac{x+7}{2003}-3
Đọc tiếp
\(\dfrac{x+5}{2005}\)+\(\dfrac{x+6}{2004}\)+\(\dfrac{x+7}{2003}\)=-3
x+3/2003+x+2/2004+x+1/2005=-3
(1/2003+1/2004-1/2005)/(5/2003+5/2004-5/2005)-(2/2002+2/2003-2/2004)/(3/2002+3/2003-3/2004)
tính
a/1/2x+3/5x=-33/25 b/(2/3x-4/9)(1/2+(-3/7):x)=0
c/x+5/2005+(x+6/2004)+(x=7/2003)=-3
\(\frac{x+6}{2001}+\frac{x+5}{2002}+\frac{x+4}{2003}=\frac{x+3}{2004}+\frac{x+2}{2005}\)+\(\frac{x+1}{2006}\)
Tìm x
Tìm x biết : \(\frac{x+5}{2005}+\frac{x+6}{2004}+\frac{x+7}{2003}=-3\)
tìm x biết :\(\frac{x-1}{2005}+\frac{x-2}{2004}-\frac{x-3}{2003}=\frac{x-4}{2002}\) Giúp mình với