\(x+50-2\times3=54\)
\(x+50-2=54\div3\)
\(x+50-2=18\)
\(x+50=18+2\)
\(x+50=20\)
\(x=20-50\)
\(x=-30\)
Hình như sai do lớp 3 chưa học âm
X + 50 - 2x3 = 54
X + 50 = 54 + 6
X + 50 = 60
X = 60 - 50
X = 10
x+50-2x3=54
x+50-6=54
x+50=54+6
x+50=50
x=60-50
x=10
Mình nhầm :
\(x+50-2\times3=54\)
\(x+50-6=54\)
\(x+50=54+6\)
\(x+50=60\)
\(x=60-50\)
\(x=10\)
\(x+50-2\times3=54\)
\(x+50-6=54\)
\(x+50=54+6\)
\(x+50=60\)
\(x=60-50\)
Vậy x=10
X + 50 - 2 x 3 = 54
X + 50 - 6 = 54
X + 50 = 54 + 6
X + 50 = 60
X= 60 - 50
X = 10