Để \(\frac{x+5}{x-2}\)là số nguyên thì x+5 phải chia hết cho x-2
x+5 chia hết cho x-2
x-2+7 chia hết cho x-2
-> 7 chia hết cho x-2
=> x-2 \(\in\)Ư{7} = -7; -1; 1; 7
* Nếu x-2=-7 => x= -5
* Nếu x-2=-1 => x= 1
* Nếu x-2=1 => x= 3
* Nếu x-2=7 => x= 9
Vậy để \(\frac{x+5}{x-2}\)là số nguyên thì x\(\in\){-5; 1; 3; 9}
nha!
tim cac so nguyen x de ( A=x+4/x-2)+(2x+5/x-2) la 1 so nguyen
tim so nguyen x de phan so sau la so nguyen x+3/x-2
A = 2/ x-1 .tim dieu kien cua x de A la phan so . tim A khi x = 2 ; x = -3. tim dieu kien cua x de A la so nguyen ( A thuoc Z )
Tim so nguyen x de A la so nguyen, biet: A=13:(x-2)
tim x la so nguyen de 13/x-5 =1 so nguyen
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
TIM CAC SO NGUYEN X DE BIEU THUC SAU LA SO NGUYEN:
A=6 /X-2
B=X+1/X-2
C=X-5/X+2
MK CAN GAP LM NHANH GIUP MK!!!
bai 1:tim so nguyen x sao cho gia cua cac phan so la so nguyen
a)x+3/x-2
b)x2+3x-2/x+2
chu y:dau / la dau chia trong phan so
bai 2:cho A=2n+1/n-2 voi n la so nguyen
a)tim n de a la phan so
b)tim n de A nguyen
c)tinh gia tri cua A biet:n=2;1;-2;-1
giup minh voi minh dang can.Ai dung minh tick cho
Tim so tu nien x de so x-2;5x-2 la so nguyen to
cho bieu thuc M 3x-4
x-4
a) tim so nguyen x de m la mot so nguyen
b)tim so nguyen x de m la 1 phan so
