\(x^5=32\)
\(\Rightarrow x=2\), vì \(2^5\)= 2.2.2.2.2 = 32
Vậy x = 2
\(3^x.3=243\)
\(3^x=243:3\)
\(3^x=81\)
\(\Rightarrow x=4\)
Vậy x = 4
\(2^x.7=56\)
\(2^x=56:7\)
\(2^x=8\)
\(\Rightarrow x=3\)
Vậy x = 3
a) \(x^5=32\)
\(\Rightarrow x^5=2^5\)
\(\Rightarrow x=2\)
b) \(3^x.3=243\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\Rightarrow x=4\)
c) \(2^x.7=56\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\Rightarrow x=3\)
x^5-(32)=0
(x4 + 2x3 + 4x2 + 8x + 16) • (x - 2) = 0x4+2x3+4x2+8x+16 = 0
x-2=0
x=2
3*x*(3/10)-(243)=0
(3x • \(\frac{3}{10}\)) - 243 = 0 9x - (243 • 10) 9x - 2430 ——————————————— = ————————— 10 109x - 2430 = 9 • (x - 270)
9 • (x - 270) ————————————— = 0 10
9•(x-270)
————————— • 10 = 0 • 10 10x-270 = 0
x=270
2*x*(7/10)-(56)=0
(2x • \(\frac{7}{10}\)) - 56 = 0 7x - (56 • 5) 7x - 280————————————— = ———————— 5 57x - 280 = 7 • (x - 40)
7 • (x - 40) ———————————— = 0 5 7•(x-40) ———————— • 5 = 0 • 5 57 • (x-40) = 0
x-40 = 0
x=40
học tốt
ko chắc nhé
\(x^5=32=>\) \(x^5=2^5vì\) \(2.2.2.2.2=32\)VẬY : \(x^5=2^5\)
\(3^x.3=243=>3^x=3^4vì\)\(3.3.3.3=81.3=243\)VẬY : \(3^x=3^4\)
\(2^x.7=56=>2^x=2^3vì\)\(2.2.2=8.7=56\)VẬY : \(2^x=2^3\)
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