\(\left(x+5-19\right)+\left(x+3+24\right)=125\)
\(x+5-19+x+3+24=125\)
\(2x+8+5=125\)
\(2x+13=125\)
\(2x=125-13\)
\(2x=112\)
\(x=112\div2\)
\(x=56\)
(x+5-19)+(x +3 +24)=125
x-(19-5) + x+27 =125
x-14 + x+27=125
x+x-14+27=125
x x2 +27-14=125
x x2 +13=125
x x2=125-13=112
x=112 :2=56
\(\left(x+5-19\right)+\left(x+3+24\right)=125\)
\(\Rightarrow x-14+x+27=125\)
\(\Rightarrow\left(x+x\right)+\left(27-14\right)=125\)
\(\Rightarrow2\times x+13=125\)
\(\Rightarrow2\times x=125-13\)
\(\Rightarrow2\times x=112\)
\(\Rightarrow x=112:2\)
\(\Rightarrow x=56\)
Vậy \(x=56\)
~ Ủng hộ nhé
\(\left(x+5-19\right)+\left(x+3+24\right)=125\)
\(\left(x\cdot2\right)-14+27=125\)
\(\left(x\cdot2\right)+13=125\)
\(\left(x\cdot2\right)=125-13=112\)
\(x=112:2\)
\(x=56\)
