\(x+4x+7x+...+100x=8585\)
\(\Leftrightarrow x\left(1+4+7+...+100\right)=8585\)
\(\Leftrightarrow\frac{\left(100+1\right)\left[\left(100-1\right)\div3+1\right]}{2}x=8585\)
\(\Leftrightarrow\frac{101.34}{2}x=8585\)
\(\Leftrightarrow101.17x=8585\)
\(\Leftrightarrow1717x=8585\)
\(\Leftrightarrow x=\frac{8585}{1717}\)
\(\Leftrightarrow x=5\)
Vậy x = 5
Tìm x biết 7x+8x+9x+...+100x=1025
(2020-4x)/x=100x timf x
BÀI 1:Tìm x biết
a :3x -5 =x
b: 1.2.3.4.5......(x+1)=0
c:x+ 2x +3x +4x +5x+..............+100x=0
d:x +2x+3x+4x+5x+..................+100x=5050
e:(x+1)+(x+2) +(x+3) +(x+4)+............+(x+100)= 5050
Tìm x biết x+2x+3x+4x+...+100x=5050
tìm số tự nhiên x biết : x+2x+3x+4x+...+100x = 10100
tìm x
x+2x+3x+4x+.....+100x=151500
Tìm x,biết:
2x+4x+6x+...+98x+100x=51.102
Tìm x thuộc N
1x+2x+3x+4x+.........+100x=10100
cac ban oi giai cho mik bai nay zoi
2x+4x+6x+...+100x=50x100
cam on cac ban nhiu lam
a quen de bai la tim x nhe
