Question

\(x^4+64\)Phân tích đa thức thành nhân tử

Answer 1

hdt thức nha bạn

~~~~~~~~~~~~~

^_^

Answer 2

\(x^4+64\)

\(=\left(x^2\right)^2+8^2+2x^2.8-2x^2.8\)

\(=\left(x^2+8\right)^2-\left(4x^2\right)\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

Answer 3

\(x^4+64\)

\(=\left(x^4+16x^2+64\right)-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

Answer 4

\(x^4+64\)

\(=x^4+16x^2+64-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)