\(\left(x+\frac{3}{5}\right).4=\frac{8}{3}\)
\(x+\frac{3}{5}=\frac{8}{3}.\frac{1}{4}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{3}{5}=\frac{10}{15}-\frac{9}{15}=\frac{1}{15}\)
\(\left(x+\frac{3}{5}\right).4=\frac{8}{3}\)
\(\Rightarrow x+\frac{3}{5}=\frac{8}{3}:4=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}-\frac{3}{5}=\frac{1}{15}\)
Vậy \(x=\frac{1}{15}\)
Ủng hộ tớ nha
\(\left(x+\frac{3}{5}\right)\times4=\frac{8}{3}\)
\(\left(x+\frac{3}{5}\right)=\frac{8}{3}\div4\)
\(x+\frac{3}{5}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{3}{5}\)
\(x=\frac{1}{15}\)
Vậy \(x=\frac{1}{15}\)
\(\left(x+\frac{3}{5}\right)\times4=\frac{8}{3}\)
\(\Rightarrow x+\frac{3}{5}=\frac{8}{3}:4\)
\(\Rightarrow x+\frac{3}{5}=\frac{8}{3}\times\frac{1}{4}\)
\(\Rightarrow x+\frac{3}{5}=\frac{8\times1}{3\times4}\)
\(\Rightarrow x+\frac{3}{5}=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}-\frac{3}{5}\)
\(\Rightarrow x=\frac{10}{15}-\frac{9}{15}\)
\(\Rightarrow x=\frac{1}{15}\)
Vậy \(x=\frac{1}{15}\)
