\(\left|x+\dfrac{3}{4}\right|-\dfrac{1}{2}=0\\ =>\left|x+\dfrac{3}{4}\right|=\dfrac{1}{2}\\ =>\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{1}{2}\\x+\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.=>\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=-\dfrac{5}{4}\end{matrix}\right.\)