\(3\left(x^2-2xy+y^2-4z^2\right)\)
\(\:dong3\\ =2x^2+3x-2-3=2 x\left(x-1\right)+3\left(x-1\right)=\left(2x+3\right)\left(x-1\right)\)
\(2x^2-18=2\left(x^2-9\right)\)
\(x^2-7xy+10y^2=\)
câu cuối mk biết làm rồi
\(x^2-7xy+10y^2\)
\(=x^2-2xy-5xy+10x^2\)
\(=\left(x-5y\right)\left(x-2y\right)\)