(x + 3)(2x - 7) = 0
=> \(\orbr{\begin{cases}x+3=0\\2x-7=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0-3\\2x=0+7\end{cases}}\)
=> \(\orbr{\begin{cases}x=-3\\2x=7\end{cases}}\)
=> \(\orbr{\begin{cases}x=-3\\x=7\div2\end{cases}}\)
=> \(\orbr{\begin{cases}x=-3\\x=\frac{7}{2}\end{cases}}\)
(x+3)(2x-7)=0
=>x+3=0 hoac2x-7=0
x=0-3 2x=0+7
x=-3 2x=7
x=7:2
x=3,5