Question

(x^3 - 2x^2 + 3x+2-a) : (x-2)

Answer 1

Để \(\left(x^3-2x^2+3x+2-a\right)⋮\left(x-2\right)\)

\(\Leftrightarrow x^3-2x^2+2x+2-a=\left(x-2\right)\cdot a\left(x\right)\)

Thay \(x=2\Leftrightarrow8-8+6+2-a=0\Leftrightarrow8-a=0\Leftrightarrow a=8\)

Answer 2

 

Theo định lý Bezout, ta có:

2^3 - 2.2^2 + 3.2 + 2 - a = 0

a=8