\(=\left[\left(x+2\right)\left(x+5\right)\right]\left[\left(x+3\right)\left(x+4\right)\right]-8\\ =\left(x^2+7x+10\right)\left(x^2+7x+12\right)-8\\ =\left(x^2+7x+11\right)^2-1-8\\ =\left(x^2+7x+11\right)^2-9\\ =\left(x^2+7x+11-3\right)\left(x^2+7x+11+3\right)\\ =\left(x^2+7x+8\right)\left(x^2+7x+14\right)\)