Question

\(x^2+x=0\)

Answer 1

\(x^2+x=0\)

\(x_1=-1\left(-1^2=0\right)\)

\(x_2=0\)

\(=>-1^2+0=0+0=0\)

Answer 2

x²  + x = 0

x=0

Answer 3

thao em thi x=0

Answer 4

Ta có : x² + x = 0

<=> x.(x+1)=0 <=> \(\orbr{\begin{cases}x=0\\x+1=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=0\\x=-1\end{cases}}\)

Answer 5

\(x^2+x=0\)

=>\(x\left(x+1\right)=0\)

=>\(x=0\)hoặc \(x+1=0\)

                         =>\(x=1\)