Question

\(x^2+x=0\)

Answer 1

x²+x=0

=>x(x+1)=0

=>x=0 hoặc x+1=0

x=0 hoặc x=-1

Answer 2

Vậy x = 0

Answer 3

\(x^2+x=0\)

\(\Rightarrow x.\left(x+1\right)=0\)

\(\Rightarrow\hept{\begin{cases}x=0\\x+1=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=-1\end{cases}}}\)

Answer 4

Vậy x = 0

Answer 5

\(x^2+x=0\)

\(\Rightarrow x\left(x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-1\end{cases}}}\)

Answer 6

\(x^2+x=0\Leftrightarrow x\left(x+1\right)=0\Leftrightarrow\orbr{\begin{cases}x=0\\x=-1\end{cases}}\)

Answer 7

\(x^2+1=0\)\(\Rightarrow x\left(x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-1\end{cases}}\)

k cho mình nha