Question

x²=x-20

ai nhanh tay 3 tik nhé

Answer 1

\(x^2=x-20\)

\(\Leftrightarrow x^2-x+20=0\)

\(\Leftrightarrow x^2-2.x.\frac{1}{2}+\frac{1}{4}+\frac{79}{4}\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2=-\frac{79}{4}\)

Do \(\left(x-\frac{1}{2}\right)^2\ge0\text{ }\forall\text{ }x\in R\)

Nên pt vô nghiệm

Answer 2

thank s đủ r

Answer 3

Ui ......... ngươi ta nói nó dễ ..........

\(x^2=x-20\)

\(\Leftrightarrow x^2-x+20=0\)

\(\left(a=1;b=-1;c=20\right)\)

\(\Delta=b^2-4ac\)

\(=\left(-1\right)^2-4.1.20\)

\(=-79< 0\)

Vậy phươg trình vô nghiệm