\(\frac{x}{2}+\frac{99}{2}=0\Rightarrow\frac{x}{2}=0-\frac{99}{2}\Rightarrow\frac{x}{2}=\frac{-99}{2}\Rightarrow x=-99\)
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Các câu hỏi tương tự
x/2 +99/2=0.Vay x=
x/2+99/2=0
1.a)(x+3/5).(x+1)<0
b)(x-1/3).(x+2/5)>0
2.B=(1-2/5).(1-2/7).(1-2/9).....(1-22/99)
1.a)(x+3/5x+1)<0
b)(x-1/3).(x+2/5)>0
2.B=(1-2/5).(1-2/7).(1-2/9).....(1-22/99)
4 Tìm x :
(x+2).(4-x)=0 ; d) (x+1)+(x+3)+(x+5)+...+(x+99)=0
( 3x -2) (2x+3)-(6x^2-85)-99 =0
2x+2(-(-x+3*(x-3)))=2
giá trị x thỏa mãn
\(\frac{x}{2}+\frac{99}{2}=0\)
Tìm x
(3x-2).(2x+3)-(6x2-85)-99=0
Tìm x biết:
a) | 2x - 5 | + | y - 3 | = 0
b. | 2x - y + 1| ^3 + ( 2 - 3y )^2 = 0
c. | x + 1 / 1x2 | + |x + 1/2x3 | +.....+ |x+1/99+100 | = 100x