\(\left|x^2+8\right|=9\Leftrightarrow x^2+8=\left|9\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+8=9\Leftrightarrow x^2=1\Leftrightarrow x=\pm1\\x^2+8=-9\Leftrightarrow x^2=-17\Rightarrow x=\varnothing\end{matrix}\right.\) Vì \(x^2\ge0\) với mọi x
➤\(x=\pm1\)