\(x^2+2x+3=0\)
\(\Rightarrow\left(x^2+2x+1\right)+2=0\)
\(\Rightarrow\left(x+1\right)^2+2=0\)(vô lý do \(\left(x+1\right)^2+2\ge2>0\))
Vậy \(S=\varnothing\)
Tìm x
1) (2x-1)(x+3)(2-x)=0
2)x^3 + x^2 + x + 1 = 0
3) 2x(x-3)+5(x-3) =0
4)x(2x-7)-(4x-14)=0
5) 2x^3 + 3x^2 + 2x + 3 = 0
Tìm x
(2x-3).(x+1)-2x^2+6x=0
(X^2-x+1).(x-3)-x^3+4x^2=0
(X^2-2).(x^2+2)-x^4-2x+5=0
(X-3).(x^2-3x+2)-(x^2-2x-7).(x-2)+2x^2-2x=0
A) 2x³+6x²=x²+3x
B) (2x+5)²=(x+2)²
C) x²-5x+6=0
D) (2x-7)²-6(2x-7)(x-3)=0
E) (x-2)(x+1)=x²-4
G) 2x(2x-3)=(3-2x)(2-5x)
H) (1-x)(5x+3)=(3x-7)(x-1)
F) (x+6)(3x-1)+x+6=0
I) (4x-1)(x-3)=(x-3)(5x+2)
K) (x+4)(5x+9)-x-4=0
H) (x+3)(x-5)+(x+3)(3x-4)=0
M) (2x+3)(-x+7)=0
Tìm x
a,x(x-2)-x(x-1)(x-3)=0
b,(2x-5).(x+3)-(x-1).(2x+3)=0
c,(x-2)(x^2+2x+8)-x^3-2x+1=0
tìm x
a) ( 2x - 3 ) * ( x + 1 ) - x ( 2x + 3 ) - 9 = 0'
b) 2x ( x - 3 ) - x - 3 = 0
c) 2x * ( x^2 - 4 ) + 6 ( 4 - x^2)=0
Tìm x:
a, 3x (4x -3) - 2x (5-6x) = 0
b, 5 (2x-3) + 4x (x-2) + 2x (3-2x) = 0
c, 3x (2-x) + 2x (x-1) = 5x (x+3)
d, 3x (x+1) - 5x (3-x) + 6(x2 + 2x + 3) = 0
Giải các phương trình sau a.(2x-5)(12+5x)=0 b(x-3)(x-4)-2(x-3=0 c.x(x-1)(x+1)=0 dù.2x/3+2x-1/6=0
1, x(2x-7)-4x+14=0 2, x+x^2-x^3-x^4=0
3, 2x^3+3x^2+2x+3=0 4, 4x^2 - 25 - (2x-5)(2x+7)=0
a,2x(x-3)+5(x-3)=0
b,(x^2-4)+(x-2)(3-2x)=0
c,x^3-3x^2+3x-1=0
d,x(2x-7)-4x+14=0
e,(2x-5)^2-(x+2)^2=0
f,x^2-x-(3x-3)=0
Giups mình giải bài này nhé?
a)x2+3x+6=0
b)x2-2x-3=0
c)2x2+7x+3=0
d)x3-2x2-x+2=0
e)x4.(x-1)-2x.(x-3)-9(x-1)=0
