Question

x²+2x-2=0

 

Answer 1

\(x^2+2x+1-3=0\\ \left(x+1\right)^{^2}=3\\ \left[{}\begin{matrix}\left(x+1\right)^2=\left(\sqrt{3}\right)^2\\\left(x+1\right)^2=\left(-\sqrt{3}\right)^2\end{matrix}\right.=>\left[{}\begin{matrix}x+1=\sqrt{3}\\x+1=-\sqrt{3}\end{matrix}\right.=>\left[{}\begin{matrix}x=\sqrt{3}-1\\x=-\sqrt{3}-1\end{matrix}\right.\)