Ix2+2I=6
tach ra 2 truong hop
x2+2=6 hay x2+2=-6
x2 =6-2 x2 =-6-2
x2 =4 x2 =-8
=> x =+2 => x khong thoa man
Vay x=2 hoac x=-2
TH1: x2 + 2 = 6 => x2 = 4 => x = 2, x = -2
TH2 : x2 + 2 = - 6 => x2 = -8 (vô lý)
Vậy pt có 2 nghiệm x = 2 ; x = -2
TH1: \(x^2+2=-6\)
\(x^2=-6-2\)
\(x^2=-8\)
=> \(x^2=2^3\)
x ko thỏa mãn!!!!
TH2: \(x^2+2=6\)
\(x^2=6-2\)
\(x^2=4\)
\(x^2=2^2\)
=> x=2
Vậy x=2