\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
\(\Rightarrow\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}-\frac{x+2}{14}-\frac{x+2}{15}=0\)
\(\Rightarrow\left(x+2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)=0\)
\(\Rightarrow x+2=0\left(\text{Vì }\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\ne0\right)\)
=>x=-2
Vậy x=-2
x+2/11+x+2/12+x+2/13=x+2/14+x+2/15
=>x+2/11+x+2/12+x+2/13-x+2/14-x+2/15=0
=>(x+2).(1/11+1/12+1/13-1/14-1/15)=0
mà 1/11>1/12>1/13>1/14>1/15
=>1/11+1/12+1/13-1/14-1/15 khác 0
=>x+2=0
=>x=-2
vậy x=-2
\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
\(\Rightarrow\)\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}-\frac{x+2}{14}-\frac{x+2}{15}=0\)
\(\Rightarrow\)\(\left(x+2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)\)
\(\Rightarrow\)\(x+2=0\left(vi\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\ne0\right)\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
x+2/11+x+2/12+x+2/13=x+2/14+x+2/15
=>x+2/11+x+2/12+x+2/13-x+2/14-x+2/15=0
=>(x+2).(1/11+1/12+1/13-1/14-1/15)=0
mà 1/11>1/12>1/13>1/14>1/15
=>1/11+1/12+1/13-1/14-1/15 khác 0
=>x+2=0
=>x=-2
vậy x=-2
