\(x^{2018}+2x^{2017}+3x^{2016}+...+2017x+2018\)
\(=1+2+3+...+2017+2018\)
\(=\frac{2018.\left(2018+1\right)}{2}=2037171\)
\(x^{2018}+2x^{2017}+3x^{2016}+...+2017x+2018\)
\(=1+2+3+...+2017+2018\)
\(=\frac{2018.\left(2018+1\right)}{2}=2037171\)
tim GTNN cua bieu thuc A=x-2017|x - 2017| + |x - 2018| + |x - 2019|
|3x-2018| + |x-2017| = |2x -1|
|x-1| + |x-3| +|x-5| +|x-7| = 8
|x-2018| + |x-2017| + |x-2018| = 2
MOi nguoi giup minh voi 4gio minh can roi
tinh gia tri bieu tuc
P= 2018. x2016 . y2017 - (z -1 )2018 , biet ( x+ 1)6 + (y-1)4 = -z2
giup mk gap 5 tick nha giai chi tiet nhe tinh gia tri cua da thuc P(x)= x^2018 + x^2017 + x^2016 + .... + x^2 + x + 1 tai x=1
Cac ban giup minh voi minh can nop gap
Tim gia tri nho nhat cua bieu thuc:
P= / x-1/+/x-2017/+/x-2018/
* Dau gach cheo la dau gia tri tuyet doi nhe
Tinh gia tri cua bieu thuc sau:
\(C=x^{2010}-2015x^{2009}-2015x^{2018}-.....-2015x+1\)tai x=2016
Giup to nha!!!!!!!!!!!!Mai di hoc oy!!!!!!!!!!!!!!!
cho xyz la cac so thuc thoa man y+z+1/x=x+z+2/y=x+y+2/z=1/x+y+z tinh gia tri bieu thuc A=2016.x+y^2017+z^2017
cho đa thức f(x)=x^8 - 2017x^7 +2017x^6 - 2017x^5 +...+2017x^2 - 2017x + 2018.Tính f(2016)
Tính tổng:
x+2x+3x+4x+...+2017x=2016*2017