Question

(x+20)^100+|y+4|=0

 

Answer 1

<=>(X+20)^100=0

=>X+20=0

<=>|Y+4|=0=>Y+4=0

=>X=-20

=>Y=-4

Answer 2

Vì \(\left(x+20\right)^{100}\ge0;\left|y+4\right|\ge0\)

\(\Rightarrow\left(x+20\right)^{100}+\left|y+4\right|\ge0\)

Dấu "=" xảy ra <=> \(\orbr{\begin{cases}\left(x+20\right)^{100}=0\\\left|y+4\right|=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x+20=0\\y+4=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=-20\\y=-4\end{cases}}}\)

Vậy x = - 20; y = - 4