Question

x^2 - x + 1/4 = 0

Tìm x

Answer 1

x² - x + 1/4 = 0

=> x² - 2.x.1/2 + (1/2)² = 0

=> (x - 1/2)² = 0

=> x - 1/2 = 0

=> x = 1/2

Vậy x = 1/2 !!!

Answer 2

x²-x+\(\frac{1}{4}\)=0

suy ra x²-x=0-\(\frac{1}{4}\)=\(\frac{-1}{4}\)

x-x=\(\frac{-1}{4}\)/2=\(\frac{-1}{8}\)

x=\(\frac{-1}{8}\)/2=\(\frac{-1}{16}\)

Answer 3

\(x^2-x+\frac{1}{4}=0\)

\(\Leftrightarrow x^2-2.\frac{1}{2}x+\left(\frac{1}{2}\right)^2=0\)

\(\Leftrightarrow\left(x+\frac{1}{2}\right)^2=0\)

\(\Leftrightarrow x+\frac{1}{2}=0\)

\(\Leftrightarrow x=-\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)