\(x.2+\left(-\frac{9}{25}\right)=\frac{2}{5}.\frac{8}{5}\)
\(\Leftrightarrow x.2+\left(-\frac{9}{25}\right)=\frac{16}{25}\)
\(\Leftrightarrow x.2=1\)
\(\Leftrightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
\(x.2+\left(-\frac{9}{25}\right)=\frac{2}{5}.\frac{8}{5}\)
\(\Leftrightarrow2x+\left(-\frac{9}{25}\right)=\frac{16}{25}\)
\(\Leftrightarrow2x=\frac{16}{25}+\frac{9}{25}\)
\(\Leftrightarrow2x=1\)
\(\Leftrightarrow x=\frac{1}{2}\)
