Question

x² - 9 - ( x- 3)( 2x-5)=0

Answer 1

\(x^2-9-\left(x-3\right)\left(2x-5\right)=0\\ =>\left(x-3\right)\left(x+3\right)-\left(x-3\right)\left(2x-5\right)=0\\ =>\left(x-3\right)\left(x+3-2x+5\right)=0\\ =>\left(x-3\right)\left(8-x\right)=0\\ =>\left[{}\begin{matrix}x-3=0\\8-x=0\end{matrix}\right.=>\left[{}\begin{matrix}x=3\\x=8\end{matrix}\right.\)

Answer 2

x2−9−(x−3)(2x−5)=0=>(x−3)(x+3)−(x−3)(2x−5)=0=>(x−3)(x+3−2x+5)=0=>(x−3)(8−x)=0=>[x−3=08−x=0=>[x=3x=8