x2 + 6x - 3 (x+6)=0
=>x(x+6)-3(x+6)=0
=>(x-3)(x+6)=0
=>x-3=0 <=> x=3
hoặc x+6=0 <=> x=-6
Vậy x thuộc {-6; 3}
\(\Leftrightarrow x\left(x+6\right)-3\left(x+6\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-6\end{matrix}\right.\)