x2 + 5x = 0
x(x + 5) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x+5=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=-5\end{cases}}\)
\(x^2+5x=0\)
\(x\in\left(-\infty;\infty\right)\)
\(x\left(x+5\right)=0\)
\(x=-5\)
\(D=b^2-4ac\)
\(\left(5\right)^2-\left(4.1.0\right)=25\)
\(x_{1,2}=\frac{b+_-\sqrt{D}}{2a}=\frac{+_-\sqrt{25}+\left(-5\right)}{2}\)
\(x=-5\)
\(x=0\)
x2 + 5x = 0
x.(x + 5) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x+5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=-5\end{cases}}\)
x^2 + 5x =0 <=> x(x + 5) = 0 <=> x = 0 hoăc x + 5 = 0 <=> x = 0 hoăc x = -5 bn nhé
