`x^2 - 3x = 0`
`<=> x(x-3) =0`
`<=>` \(\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
`x^2 -3x =0`
`<=> x(x-3) =0`
`<=> [(x=0)(x-3=0):}`
`<=> [(x=0),(x=3):}`
Vậy `x in {3;0}`
tìm x
(x+4)(8-x)(3x-30)≤0
(2x-4)(15-3x)(4+x)>0
(15+3x)(6-x)(15+x)(x-6)≤0
Bài 4: Tìm x:
1) x2 - 9x = 0 2) x(x - 4) – x2 = 7 3) 3x + 2(x – 5) = 5
4) 25x2 - 1 = 0 5) 3x(x - 2) - 5(x - 2) = 0 6) 3x(x - 7) + 4(x – 7) = 0
7) 4x2 – 9 = 0 8) 10x(x - 4) + 2x - 8 = 0 9) x(2x - 5) - 2x2 = 0
10) 2x2 – 4x = 0 11) 2x(3 - 4x) + 3(4x - 3) = 0 12) 2x (x – 5) – 2x2 = 3
mọi người giúp mình vs chiều 1g mình thi rồi! cảm ơn!
Tìm x
Y) x^2-x-6=0
Z) 3x² –5x–8=0
J) 25x^2-4=0
R) 2(x+3)-x^2-3x=0
U. x³–3x² –x+3=0
Giúp mik vs mình cần gấp
Tìm x
a)3x(x-2)+2(2-x)=0
b)5x(3x-1)+x(3x-1)-2(3x-1)=0
Tìm x:
a,x(3x-5)=0
b,3x^2-27=0
c,(x-5)^2=x-5
d,2(x+7)-x^2-7x=0
e,7x(x-3)+2(3x)=0
Tìm x :
a) 3x(x-1)+x-1=0
b)2(x+3)-x^2 - 3x = 0
Tìm x:
C, X^2-9=2×(x+3)^2
b, x^3-3x^2+3x-1=0
d, x^2-8x+3x-24=0
Giúp mk với. Mk cảm ơn
Tìm x : (3x+2).(x+1)=3x.(5+x)
tìm x : 2x^2-7x+5=0
BT2: Tìm x 2, 3x(x-4)+2x-8=0 3, 4x(x-3)+x^2-9=0 4, x(x-1)-x^2+3x=0 5, x(2x-1)-2x^2+5x=16
