Question

(x^2-1)/(x^2+1) = 3/4 Giúp mình nhé mình tick cho

Answer 1

\(\frac{x^2-1}{x^2+1}=\frac{3}{4}\)

\(\Leftrightarrow4\left(x^2-1\right)=3\left(x^2+1\right)\)

\(4x^2-4=3x^2+3\)

\(x^2=7\)

\(x=\pm\sqrt{7}\)