`x^2-16=0`
`x^2=16`
`@TH1:x^2=4^2`
`=>x=4`
`@TH2:x^2=(-4)^2`
`=>x=-4`
Vậy `x=4` hoặc `x=-4`
\(x^2-16=0\\ x^2-4^2=0\\ \left(x+2\right)\left(x-2\right)=0\\ th1:x+2=0\\ x=-2\\ th2:x-2=0\\ x=2\)
\(x^2-16=0\)
\(x^2\) \(=0+16=16\)
\(x\) \(=\sqrt{16}=\pm4\)