Question

(x+1)+(x+3)+(9x+5)+............+(x+99)=0

 

Answer 1

(x + 1) + (x + 3)  +..... + (x + 99) = 0

x + 1 + x + 3 + .... + x + 99 = 0

(x + x + x + .... + x) + (1 + 3 + 5 + .... + 99) = 0

50x + 50 x (99 + 1) : 2=  0

50x + 2500 = 0

50x = 0 - 2500

50x = -2500

x = -50 

Answer 2

sai de roi

 

Answer 3

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