(x+1)+(x+2)+...+(x+98)+(x+99)=9900
x+x+x+x+...x+(1+2+...+98+99)=9900
50x+2500=9900
=>50x=7400
vậy x=148
(x+1)+(x+2)+...+(x+98)+(x+99)=9900
x+x+x+x+...x+(1+2+...+98+99)=9900
50x+2500=9900
=>50x=7400
vậy x=148
Tìm x biết ( x + 1 ) + ( x + 2 ) + .......+ ( x + 98 ) + ( x + 99) = 9900
2*x+5*x-3*x=125:4+27:3
(x+1)+(x+2)+...+(x+98)+(x+99)=9900
(x+1)+(x+2)+...+(x+98)+(x+99)=9900
giải chi tiết giúp mình hen mình cảm ơn
B = 3/2 x 12 + 3/3 x 20 + 3/4 x 30 + ... + 3 /97 x 9702 + 3/98 x 9900
Tìm x:
\(\frac{x-1}{99}\)+\(\frac{x-2}{98}+\frac{x-5}{95}=3+\frac{1}{99}+\frac{1}{98}+\frac{1}{95}\)
1 x 2 x 3 x .... x 98 x 99 x 100
Tính tổng :
S = 1 x 2 + 2 x 3 + 3 x 4 + .... + 98 x 99 + 99 x 100
1/1 x 1/2 + 1/2 x 1/3 + 1/3 + 1/4 + .......... + 1/9 x 1/10
2/1 x 2 + 2/2 x 3 + 2/3 x4 + .............. + 2/98 x 99 + 2/99 x 100
1/1 x 10 + 1/2 x 15 + 1/3 x 20+...........................................+1/98 x 495 + 1/99 x 500