\(\left(x+1\right)^2+\dfrac{3}{25}=\dfrac{19}{25}\\ \left(x+1\right)^2=\dfrac{19}{25}-\dfrac{3}{25}\\ \left(x+1\right)^2=\dfrac{16}{25}\\TH1: \left(x+1\right)^2=\left(\dfrac{4}{5}\right)^2\\x+1=\dfrac{4}{5}\\ x=\dfrac{4}{5}-1\\ x=\dfrac{-1}{5}\\ TH2:\left(x+1\right)^2=\left(\dfrac{-4}{5}\right)^2\\ x+1=\dfrac{-4}{5}\\ x=\dfrac{-4}{5}-1\\ x=\dfrac{-9}{5} \)
Lời giải:
$(x+1)^2+\frac{3}{25}=\frac{19}{25}$
$(x+1)^2=\frac{19}{25}-\frac{3}{25}=\frac{16}{25}=(\frac{4}{5})^2=(\frac{-4}{5})^2$
$\Rightarrow x+1=\frac{4}{5}$ hoặc $x+1=\frac{-4}{5}$
$\Rightarrow x=\frac{-1}{5}$ hoặc $x=\frac{-9}{5}$
`(x+1)^2+3/25=19/25`
`=>(x+1)^2=19/25-3/25`
`=>(x+1)^2=16/25`
`=>(x+1)^2=(4/5)^2` hoặc `(x+1)^2=(-4/5)^2`
`=>x+1=4/5` hoặc `x+1=-4/5`
`=>x=4/5-1` hoặc `x=-4/5-1`
`=>x=4/5-5/5` hoặc `x=-4/5-5/5`
`=>x=-1/5` hoặc `x=-9/5`
Vậy `x in{-1/5;-9/5}`
(x+1)2+3/25=19/25
(x+1)2 =19/25-3/25
(x+1)2 =16/25
(x+1)2 =4/52
x+1 =4/5
x =4/5-1
x=-1/5
