\(x^{192}=x\)
\(x^{198}-x=0\)
\(x.\left(x^{197}-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^{197}-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x^{197}=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x^{197}=\left(1,-1\right)\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=0\\x=-1\\x=1\end{cases}}\)
Vậy \(x\in\left\{0,1,-1\right\}\)
\(x^{192}=x\Rightarrow x=\left\{-1;0;1\right\}\)