|x + 8| = 10
=> x + 8 = 10 hoặc x + 8 = -10
=> x = 2 hoặc x = -18
vậy_
\(x+15\%x=115\)
\(\Leftrightarrow x+\frac{15}{100}x=115\)
\(\Leftrightarrow x+\frac{3}{20}x=115\)
\(\Leftrightarrow x\left(1+\frac{3}{20}\right)=115\)
\(\Leftrightarrow x\left(\frac{20}{20}+\frac{3}{20}\right)=115\)
\(\Leftrightarrow\frac{23}{20}x=115\)
\(\Leftrightarrow x=115\div\frac{23}{20}\)
\(\Leftrightarrow x=115\times\frac{20}{23}\)
\(\Leftrightarrow x=\frac{2300}{23}=100\)
\(\frac{4}{x}=\frac{-y}{6}=0,5\)
\(\Rightarrow\hept{\begin{cases}\frac{4}{x}=0,5\Leftrightarrow x=8\\\frac{-y}{6}=0,5\Leftrightarrow y=-3\end{cases}}\)
Vậy \(\left(x,y\right)\in\left\{\left(8,-3\right)\right\}\)