(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
(x+x+x+x)+(1/2+1/4+1/8+1/16)=1
4x+(1/2+1/4+1/8+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/16:4
x=1/64
tìm x , biết :
[ x + 1/2 ] + [ x + 1/4 ] + [ x + 1/8 ] + [ x + 1/16 ] = 23/16
[x+1/2]+[x+1/4]+[x+1/8]+[x+1/16]=1 tìm x
Tìm x biết; ( x + 1/2) + (x+1/4) + (x+1/8) + (x+1/16) = 1
tÌM x
(x + 1/2 ) + ( x + 1/4 ) + ( x + 1/8 ) + ( x + 1/16 ) = 1
Tìm x biết : ( x + 1/2 ) + ( x+1/4 ) + ( x+1/8 ) + ( x+1/16 ) = 1
(x+1/2) + (x+1/4) + (x+1/8) + (x+1/16) = 1
tìm x
tìm x
( x + 1/2 ) ( x + 1/4 ) + ( x + 1/8 ) + ( x + 1/16 ) = 1
tìm x biết :
( x + 1/2 ) + ( x+ 1/4 ) + ( x +1/8 ) + (x + 1/16 ) = 1
Tìm x, biết
(x+1/2) + (x+1/4) +(x+1/8)+(x+1/16)= 1
