Question

(x+12).(x-3)=0

Answer 1

mik làm luôn ko ghi đề nha

\(\Rightarrow\)\(\orbr{\begin{cases}x+12=0\\x-3=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=-12\\x=3\end{cases}}\)

Answer 2

\(\Leftrightarrow\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\Rightarrow\hept{\begin{cases}x=-12\\x=3\end{cases}}\)

Vậy \(x=-12;3\)

Answer 3

\(\left(x+12\right).\left(x-3\right)=0\)

\(\Rightarrow\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=-12\\x=3\end{cases}}\)