Question

|x|=1+2+3+4+5+...+2010 tìm x

2mũ x=2+4+6+8+10+...+2010 tìm x

697:15a+364/a=17 tìm a

Answer 1

\(\left|x\right|=1+2+3+...+2010\)

\(\left|x\right|=\frac{\left(2010+1\right).2010}{2}\)

\(\left|x\right|=2011.1005\)

\(\left|x\right|=2021055\)

\(x=\pm2021055\)

Answer 2

\(2^x=2+4+6+...+2010\)

\(2^x=\frac{\left(2010+2\right).1005}{2}\)

\(2^x=1006.1005\)

\(x=\frac{log\left(1011030\right)}{log\left(2\right)}\)(Nguồn: wolframalpha)

Answer 3

\(697\div15a+\frac{364}{a}=17\)

\(\frac{697}{15a}+\frac{5460}{15a}=17\)

\(6157=17.15a\)

\(6197=255a\)

\(a=\frac{6197}{255}\)