(x+12)2 . (x+1) = 0
Th1: x + 12 = 0
=> x = -12
TH2: x + 1 = 0
=> x = -1
Vậy x = -12 ; x = -1
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Tìm x :
1) -12 + 3 . ( -x +7 ) = -18
2) x . ( x + 7 ) = 0
3) ( -x + 5 ) . ( 3 - x ) = 0
4) ( x + 12 ) . ( x - 3 ) = 0
5) x . ( 2 + x ) . ( 7 - x ) = 0
6) ( x - 1 ) . ( x + 2 ) . ( -x - 3 ) = 0
a: (x - 11 + y)mũ 2 + (x - 1 - y)mũ 2 = 0
B: x + (-31/12)mũ 2 + (49/12)mũ 2 = 0
C:(3x - 5)mũ 100 + (2y + 1) mũ 200 nhỏ hơn bằng 0
D: (1/2x - 5)mũ 20 + (y mũ 2 - 1/4) mũ 10 nhỏ hơn bằng 0
E: 2 mũ x - 1 nhân 3 mũ x = 12 mũ x
a) |x| + |y| = 5
b) |x| + |y - 1| = 0
c) |x - 12| = 12 - x
d) |x - 1| = 0
e) 2 . |x - 1| = 0
Tìm x, y.
x . (x+7) = 0
(x+12) . (x-3) = 0
(-x + 5 ). ( 3 - x) = 0
(x - 1 ) . ( x +2) . (-3 - 3) = 0
( x - 4/5 ).( x+2 và 1/5 )= 0
x+20%x=12
1/4 - (2x+ 1/2 )^2=0
(x-1/5)^2 + 1= 3,5 : 7%
1) –45 + 5.(–2x) = 95
2) x.(12 + x).(71 – x) = 0
3) (x – 11).(x + 12).(–x – 13) = 0
4) |2.x – 15| = 7
5) –2.|x + 32| = –112
Tìm x
1/(x+12).(3-x)=0
2/(-x+5).(3-x)=0
3/x.(2+x).(7-x)=0
4/(x-1.(x+2).(-x-3)=0
Bài 1: Tìm x
1/(2.x-5)+17=6
2/10-2.(4-3x)=-4
3/-12+3.(-x+7)=-18
4/24:(3.x-2)=-3
5/-45:5.(-3-2.x)=3
6/x.(x+7)=0
7/(x+12).(x-3)=0
8/(-x+5).(3-x)=0
9/x.(2+x).(7-x)=0
10/(x-1).(x+2).(-x-3)=0
(x+12).(x-3)=0
(-x+5).(3-x)=0
x.(2+x).(7-x)=0
(x-1).(x-2).(-x-3)=0
Tìm x
1. x(x+7)=0
2. (x+12)(x-3)=0
3. (-x+5)(3-x)=0
4. x(2+x)(7-x)=0
5. (x-1)(x+2)(-x-3)=0