\(\Leftrightarrow\left[{}\begin{matrix}x+11=0\\3x=7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-11\\x=\dfrac{7}{3}\end{matrix}\right.\)
`( x + 11 ) ( 7 - 3x ) = 0`
`<=>` $\left[\begin{matrix} x+11=0\\7 - 3x =0\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x=-11\\ x=\dfrac{7}{3}\end{matrix}\right.$
Vậy `S = { -11; 7 /[3]}`
`(x + 11) . (7 - 3x) = 0`
`<=>` `x + 11 = 0 => x = -11`
`<=>` `7 - 3x = 0 => x = 7/3`