Question

(x+1)^12=2016^0

Answer 1

(x + 1)¹² = 2016⁰

(x + 1)¹² = 1

(x + 1)¹² = 1¹² = (-1)¹²

=> x + 1 thuộc { 1 ; -1}

=> x thuộc { 0 ; -2}

Vậy x thuộc { 0 ; -2}
 

Answer 2

\(\left(x+1\right)^{12}=2016^{0^{ }}\)

\(\left(x+1\right)^{12}=1\)

\(\left(x+1\right)^{12}=1^{^{ }12}\)
\(\Rightarrow x+1=1\)

x = 1 - 1

x=0