Ta có:\(\frac{x+10}{27}=\frac{x}{9}\Rightarrow\left(x+10\right).9=27x\Rightarrow9x+90=27x\)
\(\Rightarrow90=27x-9x\)
\(\Rightarrow\)\(90=18x\)
\(\Rightarrow x=90:18\)
\(\Rightarrow x=5\)
Vậy x=5 thỏa mãn
\(\frac{x+10}{27}=\frac{x}{9}\)
=>(x+10).9=27.x
=>9x+90=27x
=>27x-9x=90
=>18x=90
=>x=5
Vậy x=5