Question

(x-y)⁴+(y-2)=0

(x-y)²+(3y+9)⁶=0

mọi người ơi giúp mik với<3

Answer 1

sửa \(\left(x-y\right)^4+\left(y-2\right)^2=0\)

Dấu ''='' xảy ra khi \(\left\{{}\begin{matrix}x-y=0\\y-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y\\y=2\end{matrix}\right.\Leftrightarrow x=y=2\)

\(\left(x-y\right)^2+\left(3y+9\right)^6=0\)

Dấu ''='' xảy ra khi \(\left\{{}\begin{matrix}x-y=0\\3y+9=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=y\\y=-3\end{matrix}\right.\Leftrightarrow x=y=-3\)