\(x.4+\frac{4}{5}=\frac{73}{30}\)
\(x.4=\frac{49}{30}\)
\(x=\frac{49}{30}.\frac{1}{4}\)
\(x=\frac{49}{120}\)
Ta có:
X x4+\(\frac{4}{5}=\frac{17}{6}-\frac{2}{5}\)
X x4=\(\frac{17}{6}-\frac{2}{5}-\frac{4}{5}\)
X x4=\(\frac{17}{6}-\frac{6}{5}\)
Xx4=\(\frac{49}{30}\)
X=\(\frac{49}{120}\)
X.4 + 4/5 =17/6 - 2/5
4x + 4/5 = 73/30
4x = 73/30 - 4/5
4x = 49/30
x = 49/30 ÷4
x = 49/120
Vậy x = 49/120
~Hok tốt~