Question

x + (x+1) + (x+3) +(x+5)+...+(x+19)=310 giúp mik mik vote 5 sao nhé

Answer 1

x + (x + 1) + (x + 3) + (x + 5) + ... + (x + 19) = 310

x + x.[(19 - 1) : 2 + 1] + (19 + 1) . [(19 - 1) : 2 + 1] : 2 = 310

x + 10x + 20 . 10 : 2 = 310

11x + 100 = 310

11x = 310 - 100

11x = 210

x = 210/11

Answer 2

x+(x+1)+(x+3)+(x+5)+...+(x+19)=310

=>x+x+1+x+3+x+5+...+x+19=310

=>11x + (1+3+5+...+19)=310

=>11x+100=310

=>11x=210

=>x=\(\dfrac{210}{11}\)