\(x+\left(x+1\right)+\left(x+2\right)+...\left(x+2013\right)=2035147\)\(47\)
\(2014x+\left(1+2+...+2013\right)2035147\)
\(2014x+2027091=2035147\)
\(2014x=2035147-2027091\)
\(2014x=8056\)
\(x=8056:2014\)
\(x=4\)
x + (x + 1) + (x + 2) + ... + (x + 2013) = 2 035 147
2014x + (1 + 2 + 3 + ... + 2013) = 2 035 147
2014x + 2 026 084 = 2 035 147
2014x = 2 035 147 - 2 026 084
2 014x = 9 063
x = 9 063 : 2 014
x = 4,5
Vậy x = 4,5
=))
x+(x+1)+(x+2)+......+(x+2013)=2035147
(x+x+...+x)+(1+2+3+........+2013)=2035147
2014x+(1+2013).2013:2=2035147
2014x+2014.2013:2=2035147
2014x +1007.2013=2035147
2014x +2027091=2035147
2014x =2035147-2027091
2014x =8056
x =8056:2014
x =4
Vậy x=4
$ study well $
~ han sara~