Question

x + (x+1) + (x+2) + (x+3) + ... + (x + 2010)=0

Answer 1

\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+2010\right)=0\)

=>\(x+x+1+x+2+x+3+...+x+2010=0\)

=>\(\left(x+x+x+x+...+x\right)+\left(1+2+3+...+2010\right)=0\)

=>\(2011x+2021055=0\)

=>\(2011x=0-2021055\)

=>\(2011x=-2021055\)

=>\(x=\left(-2021055\right):2011\)

=>\(x=-1005\)

chúc bạn học tốt :)

Answer 2

x + (x+1) + (x+2) + (x+3) + ... + (x + 2010)=0

x+x+1+x+2+x+3+...+x+2010=0

(x+x+x+...+x)+(1+2+3+...+2010)=0

2011.x + 2010.2011:2=0

2011.x + 2021055=0

2011.x=-2021055

x=-1005

Answer 3

Gỉai:

X bằng:

2005