X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
x . 1999 - x = 1999 . 1997 + 1999
=> x.(1999 - 1) = 1999.(1997 + 1)
=> x.1998 = 1999.1998
=> x = 1999
vậy x = 1999
Dấu . là nhân nha
X x 1999 - x = 1999 x 1997 + 1999
X x 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X x (1998 - 1) = 1999 x (1997 + 1)
X x 1997 = 1999 x 1998
X x 1997 = 3994002
X = 3994002 : 1997
X = 1997001
x . 1999 - x = 1999 . 1997 + 1999
=> x . ( 1999 - 1 ) = 1999 . ( 1997 + 1 )
=> x . 1998 = 1999 . 1998
=> x = 1999
Vậy x = 1999
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
x . 1999 - x = 1999 x 1997 + 1999
x . ( 1999 - 1 ) = 1999 . ( 1997 + 1 )
x . 1998 = 1999 . 1998
=> x = 1999
X . 1999 - x = 1999 x 1997 + 1999
X . 1999 - X x 1 = 1999 x 1997 + 1999 x 1
X . 1997 = 1999 x 1998
X . 1997 = 3994002
X = 3994002 : 1997
X = 1997001
nha bn
X.1999-X=1999.1997+1999
X.1999-X.1=1999.1997+1999.1
X.(1999-1)=1999.(1997+1)
X.1998=1999.1998
X.1998=3994002
X=3994002:1998=1999
VẬY X=1999
thách đứa nào tích mik đc 10 k
\(x\times1999-x=1999\times1997+1999\)
\(x\times\left(1999-1\right)=1999.\left(1997+1\right)\)
\(x\times1998=1999\times1998\)
\(x=1999\times1998\div1998\)
\(x=1999\)
Vậy \(x=1999\)